# cs601 assignment 2 idea solution spring 2020

**Assignment No.2 2020
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__Question No: 1__

After carefully analyzing the following figure that represents encoding scheme based on **IEEE 802.3 Manchester** approach, you are required to identify the bit pattern associated with the given figure:

__Solution:__

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According to instruction encoding scheme is given below in the table.

1 |
0 |
1 |
1 |
1 |
0 |
1 |

**Question No: 2**

Suppose a computer in an army headquarters is transferring a file of 10 Megabits to a computer placed in a check post situated at the distance of 2000 KM. Assuming that sender and receiver computers are connected through a point to point link of 1 Gigabit and propagation speed as 2.4 × 10^{8} meters per seconds, you are required to calculate the following:

- Propagation Time
- Transmission Time

__Solution:__

**Propagation time.**

Distance = 2000 KM

Propagation Speed = 2.4 × 10^{8}m/s =

= 240000000ms^{-1}

For conversion of meter to Kilometer

Propagation Speed = 240000000/1000

= 240000Kms^{-1}

Propagation time = ?

Propagation time = Distance/propagation time

Propagation time = 2000KM/ 240000Kms^{-1}

Propagation time = 0.008333 sec

we convert it into milli second and then into microsecond.

Propagation time = 0.008333/1000 milli sec

Propagation time = 8.333 milli sec

Propagation time = 8333.33 µs

__Transmission Time:__

Message Size = 10 Megabits

Bandwidth = 1Gigabit/s

** **Bandwidth = 1000 Megabits/sec

Transmission Time = ?

Transmission time = Message Size/Bandwidth

Transmission Time = 10 Megabits/1000Megabits sec^{-1}

Transmission Time = 0.01 sec

Transmission Time = 10 millisec

Transmission Time = 10000 µs

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